When I was at the recycler last week, I saw a lot of really OLD test
equipment. I started looking through it to see if there were things I could
recognize, but the closest thing I could figure out was a 1940s telephone
equipment tester. All of these were portable, with lids that closed with
latches. Probably weighed abt 20-30 pounds each. Any cables that might have
been needed to run the equipment was gone. If things like this are of
interest in the $25 range, then I can pick some up next time I see them.
Unfortunately I have no cell phone numbers for anyone in the DFW area to
tell them to come and see the goodies while I am there, and they will not
let strangers come in and poke around. I am (or was) an electronics tech,
but most of the functions on these old test machines eluded me.
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Hi.
I'm considering to ship an empty full height rack from the USA to Sweden. It is
definitely something I wont find here so it might be worth the cost and effort.
What are my options to get it here safely? If you have any experience I would
greatly appreciate if you could share them.
Thanks in advance,
Pontus.
You should be just fine.
On 4/7/2016 1:38 PM, Bill Sudbrink wrote:
> If you have a circuit which is normally designed to
> operate with an unregulated supply, through a regulator...
> say unregulated +8 through a 7805 to a regulated +5 and
> you want to test it independent of the +8 supply, if
> you leave the unregulated rail unattached and put +5
> switcher straight onto the regulated +5 rail, will you
> damage the 7805? Clearly the VIN is open, but the ground
> pin will still be attached. Would this push voltage
> back through and screw things up?
>
> Thanks,
> Bill S.
>
>
>
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I had one of those Japanese Koan moments recently when someone asked me
"Why do floppy disks stop working?" and I realised I... didn't actually
know. I thought I'd throw it to the group and get some theories/proofs.
Let's work on the assumption we're talking about 5.25" and 3.5" disks.
Several guesses:
- Repeated use slowly wears away the magnetic media layer on the mylar.
- When left in an unprotected state, or a poor environment, damp, mold and
dust can damage the surface, either degrading the magnetic layer or
causing the gap to shrink enough that the drive head physically damages
the disk?
- Quantum fluctuations in the state of the universe, caused by millions of
mostly non-interacting particles passing through a disk in any given
minute, alter the magnetic spin of the ferric atoms causing gradual data
loss over time (mostly tongue-in-cheek)
- Given the lack of use of most floppy drives they themselves pick up
'gunk' and on first reading a diskette after a long time of disuse damage
it.
It _seems_ like when you put a 3.5" disk down for ten years and pick it
back up, a disk that used to work fine no longer does. Of course, after
ten years, it could be your own memory that's failed.
Dare I ask, what's the consensus?
- JP
> > > 1) I have a 12 volt DC supply. 12 volts seems to be
> > > within the VIN range for the 7805s whose data
> > > sheets I've now read. Can I simply apply 12 volts?
> >
> > Yes, but that regulator might get mighty hot! I would
> > not do this for fear of cooking the poor thing.
>
> That's what I figured to start with, before reading the
> datasheets.
If as your photos (in another message) suggest it will run
OK from 8V with no heatsink on the 7805, then I would be
pretty sure it will be OK at 12V if you bolt a reasonable
heatsink to the regulator. Give it a smear of silicone
grease, of course.
-tony
>
> First, a few quick "whys":
>
> 1) The 7805 is actually a Motorola MC7805CP, date
> code 7308 with gold leads. Very hard to exactly
> replace.
Any reason why it would have to be an exact replacement?
In any case, the behaviour of the 7805 if you apply a
voltage to the output with the input floating may well
depend on the manufacturer and even the date (some
devices were improved over the years). Unless you have
a 1973-or-so data sheet from Motorola, I don't think
you know whether it will be damaged or not.
[...]
> 1) I have a 12 volt DC supply. 12 volts seems to be
> within the VIN range for the 7805s whose data
> sheets I've now read. Can I simply apply 12 volts?
Yes, but... The power disipated in the 7805 will increase, in
fact it will be more than doubled. To put it crudely, a linear
regulator acts like an automatic variable resistor. I have no
idea what current the load takes, let's call it I. If you supply
8V, then the power disipated in the 7805 is 3*I watts, if you
supply 12V it's 7*I. This may or may not be a problem.
> 2) Could I place a resistor in series between the 12V
> supply and the 7805 to drop the voltage at the 7805
> to somewhere around 8?
Yes. You need to know the maximum current the load will
draw, which will be much the same as the current drawn
>from the PSU. Then just calculate the resistor to drop
4V at that current.
If you can find one, you could probably use a 7808 to supply
8V to the unit from a 12V supply. Or a 7805 'jacked up' with
a 3.3V zener diode (in series with the common lead to the
extra 7805 only).
My guess is that giving it 12V will be fine though.
What is the device, and do you have any idea how much
current it is going to draw?
-tony
> 1) The 7805 is actually a Motorola MC7805CP, date
> code 7308 with gold leads. Very hard to exactly
> replace.
Is that the big flat plastic package with the wide flat leads? I might
have a few of those around, but I agree, not an easy variant to find.
> 1) I have a 12 volt DC supply. 12 volts seems to be
> within the VIN range for the 7805s whose data
> sheets I've now read. Can I simply apply 12 volts?
Yes, but that regulator might get mighty hot! I would not do this for
fear of cooking the poor thing.
> 2) Could I place a resistor in series between the 12V
> supply and the 7805 to drop the voltage at the 7805
> to somewhere around 8?
Yes, you could do this. Pick an appropriate power resistor, or use a
big wirewound rheostat.
> 3) If I was to "tack on" a jumper between VIN and VOUT,
> would that protect the 7805 and allow me to power the
> circuit with 5 volts?
I would not do this at all.
--
Will
If one were to use a dumb CRT terminal from the early '70s regularly in
this day and age, would it be more prone to hardware failure than if it
were kept in storage or just kept to look at but powered off?
--
Eric Christopherson
Hi list,
the 17th edition of VCF Europe[0] is coming soon! It will take place on
April 30th and May 1st in Munich, Germany. Please be aware that the
information on the English version of the website might be outdated or
less detailed than on the German page, but Google Translate will help.
Also the registration for VCF Berlin[1] in October is open now. We are
looking for speakers, workshop instructors and exhibitors, both for the
regular exhibition and this year's special exhibition on computers and
languages. It will be open for visitors on Sunday, 2nd and Monday, 3rd
of October, as the 3rd October is a public holiday in Germany, but we
are thinking about inviting people to build up on Friday already and
using Saturday, 1st of October as a day just for the participants and
the community. This way there would be more time to talk and see the
other exhibitions. Maybe we could even offer advanced workshops on
Saturday. Come and visit us! Ping me if you need a place to stay.
Regards, Anke
[0] http://vcfe.org/E/index.html
[1] http://vcfb.de/2016/index.html.en