Well, yes -
since it would be drawing (to a first approximation)
Not so. There will be an out-of-phase current due to the
of the primary winding.
Yes; that's why I said "to a first approximation" - a transformer with
totally open secondaries is not quite a resistive load, but the current
drawn is generally comparatively small.
IIRC, though, you've got a leak (or short) to
earth from some point
in the HV widning, and another point on that winding (the centre-tap
of the B+ part) is deliberately earthed.
Yes - when it was in-circuit. Not when it's sitting disconnected,
which was the circumstance under which I observed the excessive draw.
That can't be right.
And I'll bet that short-to-reath is not just on
one turn, in other
words you also have shorted turns there.
I agree, especially in view of the "open-circuit" draw. :)
The Z-modulation input is an external brightness
control input, used
for some special applications.
I once built one. :) (It was a 1Kx1 RAM with circuitry to scroll
through all 1K bits, effectively turning it into a 1Kbit shift
register, with the data bit controlling the Z input on the 'scope and
the X sweep generator triggered by the carry-out from the address
counter. Get the clock frequencies about right and hook the input up
to a ham's CW sending key and you get a nice little graphic Morse
display scrolling past.)
unconnected final winding of the transformer is actually the
filament winding for the rectifier whose cathode is shown connected to
Don't you mean anode (plate to you) here?
No. Cathode, as in, the part that emits electrons. Which in a
filament valve rectifier will of necessity be the filament, so the
filament winding connected to that point will peforce be that for the
rectifier whose cathode is that filament.
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