It's pretty simple, really.
Non-polar caps are used in locations where they must pass AC. Film caps (of
various constructions) are practical until the values exceed a few uF. Once
you need more than a few uF of non-polar capacitance, it's time to look at
NP electrolytics, as they are the cheapest route to a large-ish value
without the polarity issue.
Film caps (in the 63-350V range) are available in values as large as 10uF,
22uF, 47,uF and even 100uF - or more. But those are usually high-priced
specialty audio parts, for things like speaker crossovers and output
coupling caps in some audio preamp circuits.
A non-polar electrolytic is nothing more than a pair of normal (polar)
electrolytics, with the negative (-) leads tied together. There is no
difference between a (nominal) 10uF non-polar and a pair of 22uF polars
tied neg to neg.
Pos to pos works just as well, but it's just not the standard for a very
good reason.. think about how a standard electrolytic cap case is built &
sealed..
On Mon, Aug 1, 2016 at 2:30 AM, Jim Brain <brain at jbrain.com> wrote:
On 7/31/2016 12:37 AM, Ian McLaughlin wrote:
Jim,
These are non-polarized (or bi-polar) electrolytics. An example is the
following digikey part number: 493-12697-3-ND
You can always whip one up out of your junk box - just put 2 normal
(polarized) electrolytic in series with the polarities alternating (for
example, connect the two positives together). Each capacitor has to be
twice the value of the result - so for example, to replace a 1uF 50v
non-polarized, you can put two 2uF in series.
Hope this helps.
Ian
Thank you (and Chuck) for the response.
I guess it brings up more questions for me:
* Why would Tandy spec such a cap in the design?
* As I look at the specifications of the design, it looks like the
rest of the design assume mac .250W of power on the audio line
(given the selection of resistor networks and other parts) . I
noticed the Digikey unit you referenced has 17mA of ripple current
capability. I realize audio is not truly a ripple current, but the
disparity between 17mA and 250mW seems like a problem... (Again, my
analog is severely rusty, so maybe I am looking at this wrong. I
spent all night trying to find a way to determine the power of a R2R
ladder given 5V logic and 8mA output drive of the 74ls374 IC, to no
avail, so maybe I am looking at this wrong)
o you'd think with the prevalence of R2R ladder logic, someone
would have whipped up a power calculator, if nothing else, to
determine the wattage of the resistors in the R2R, but I came up
empty... I'll have to either calculate it longhand by summing
all of the currents or sim it; not sure I can assume that since
the effective impedence is 10K, the amperage would be .5mA @ 5V
and thus the power would be 2.5mW
Sometimes, I wish I'd cared more about analog in college...
Jim