10 Sep
2003
10 Sep
'03
10:35 a.m.
3 + 5/8 if you're going to start inside V1 and
they're all 1" thick and 5
covers to go through.
wouldn't it be 3.5 inches? Starts page 1 vol 1, ends last page vol 3, so
that's only 4 covers to go thru (back of vol 1, front of vol 2, back of
vol 2, front vol 3).
So that's 3 books of pages at 1 inch per book, 3 * 1 = 3
4 covers at 1/8 per cover is 4 * 1/8 = 4/8 = 1/2
3 inches of text + 1/2 inch of covers = 3.5 inches that the worm travels.
-chris
<http://www.mythtech.net>
10 Sep
10 Sep
11:11 a.m.
On Wednesday, Sep 10, 2003, at 15:26 US/Eastern, chris wrote:
if the books are in normal array on a shelf:
back cover of vol1 | last page of vol1 | vol1 | START = 1st page of
vol1 -> front cover of vol1 -> back cover of vol2 -> vol2 -> front
cover of vol2 -> back cover of vol3 -> last page of vol3 = END | vol3 |
front cover of vol3 ----- so 4 covers and i volume for the journey -
billp
3 + 5/8 if
you're going to start inside V1 and they're all 1" thick
and 5
covers to go through.
wouldn't it be 3.5 inches? Starts page 1 vol 1, ends last page vol 3,
so
that's only 4 covers to go thru (back of vol 1, front of vol 2, back of
vol 2, front vol 3).
So that's 3 books of pages at 1 inch per book, 3 * 1 = 3
4 covers at 1/8 per cover is 4 * 1/8 = 4/8 = 1/2
3 inches of text + 1/2 inch of covers = 3.5 inches that the worm
travels.
-chris
<http://www.mythtech.net>
11 Sep
11 Sep
2:17 p.m.
chris wrote:
Unless the worm turns. :)
Btw the next volume is due around 2007.
3 + 5/8 if
you're going to start inside V1 and they're all 1" thick and 5
covers to go through.
wouldn't it be 3.5 inches? Starts page 1 vol 1, ends last page vol 3, so
that's only 4 covers to go thru (back of vol 1, front of vol 2, back of
vol 2, front vol 3).
So that's 3 books of pages at 1 inch per book, 3 * 1 = 3
4 covers at 1/8 per cover is 4 * 1/8 = 4/8 = 1/2
3 inches of text + 1/2 inch of covers = 3.5 inches that the worm travels. -chris
<http://www.mythtech.net>
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