On 9/15/2013 9:57 PM, dwight elvey wrote:
Hi Jim
You can not use 1.53 v at 5 amps to get 9v at 1 amp.
7.6VA is your input and 9VA is the output your
requesting.
Yes, you are correct. I'd like to use 1.52V @ 5A (7.6VA) to get
9VAC @
.84A. Thanks for the clarification.
Give us some more hints as to what your doing.
Trying to create 5VDC and 9VAC out of a 5VDC source.
To get 9VA out you'd need to have an input of at
least
9VA or at your 1.52V, 5.92amps.
I think we need a little more info as to why you have a
source of 1.52volts?
If I create a sine waveform (or even a square wave centered
around 0V)
using 5VDC, chopping a 5V signal using a transistor would yield 4.3V PtP
(.7v drop using the transistor). If I consider the AC voltage as
centered around the 2.15V mark, that's 2.15VAC(max). If the waveform
created is a sine (or approximation of a sine wave), I'd multiple
2.15V(max) by .707 = 1.52VAC(rms). Now, please correct me if I am
wrong, but that's how I got the measurement.
Why not just start with 110VAC?
Because the
power source at hand is 5VDC @ 10A. The 64 need 4.3A of
that, leaving a bit more than 5A for this step-up solution.
Chuck, frequency is 50/60Hz.
Jim