Hi Chuck Remeber when, I think it was you, said that we might multiply by a constant that was the fraction of ten base 2. When I looked at it, I found that it overflowed 16 bits for a number like 799. I started wacking bits off the end until I could keep it from overflowing the 16 bits. 51 was the number I found. It wasn't perfect and created an error but it was close. I wrote some code on the side ( in Forth ) to see what the worst case error was. It turns out that the remainder was worst case 13. This means that to correct the result, I only needed to multiply the result of the first calculation by 10 and then subtract that from the original number to find the error. If the error was 10 or above, I needed to increment the result and subrtact 10 from the remainder. If it was less than 10, the result was correct and I just needed to restore the remainder. I'm not sure if I did the math right at the end but it may need a little patching. The idea is sound. I think I need to use 9 instead of 10 for the subtract but I need to check it out. Oh, I forgot. the rra is because the result is 2* to large in the h register after multiplying times 51. One could shorten and only multiply by 5 but you still need to mask off to truncate. The result still needs the rra at the end but it might save a few clocks. It won't work for much over 799 before overflowing. It overflows at 1286. I figure that one might do part of the multiplication and then right shift the result some since were are going to truncate the LSBs anyway. The first result is expected to error some. With the correct value for the multiply, the error will always be on the low side, keeping the error calculation simple. The largest error seems to grow linearly so even with some truncation, one should be able to hit 10K or so with only 1 or2 conditionals, using a large fractional munber to multiply. I don't think I'd ever use this but it was fun to think about. Dwight _________________________________________________________________ Helping your favorite cause is as easy as instant messaging.?You IM, we give. http://im.live.com/Messenger/IM/Home/?source=text_hotmail_join

---snip--- Hi Chuck I just found a way to do it without any conditional at the end. I'll post it tonight when I get time. Dwight _________________________________________________________________ Connect and share in new ways with Windows Live. http://www.windowslive.com/share.html?ocid=TXT_TAGHM_Wave2_sharelife_012008