Got it; that would mean you're wanting the standard console. Right, insert jumpers A7 and A3, and also V5 and V4. They specify the device address and vector in binary. A7 is the 7th bit of the address, i.e. the 0200 bit. And since the DL11 is 'address jumper in for 0', that bit in the device's address is going to be _0_ when the jumper is in. That would turn 777770 (remember, the device is a block of 8 bytes, from xxxxx0 to xxxxx7, so you can't set the low 3 bits in the base address, they must be 0) into 777570. Similarly, A3 is 010, and turns 777770 to 777760. Put them together, you get 777560. V5 = 040, V4 = 020, so they become a vector of 060. A4 = 020, A5 = 040, A6 = 0100. V7 = 0200, V6 = 100, V3 = 010. No, but I'll whip one up and stick it on the Computer History wiki. Well, _all_ the combinations would be 2^8 combinations (there are 8 address jumpers), which is pretty sizeable, and I don't feel like listing them all, but I can list a couple of the most common ones (e.g. console, second line, etc). Noel