If a processor has 16 bit registers, 16 bit math and
address
calculation, and a 16 bit address bus, but it's ALU is only 8 bit and
its internal data bus is 8 bits, it's an 8 bit processor. Right?
wrong
--
The 360/30 /40 and /50 are all considered members of the same 32 bit
architecture, and have 8, 16 and 32 bit data paths, respectively.
An 80386/SX is not considered a 16 bit processor because it has a 16
bit data bus.
People are confusing architecture with implementation.
Is a PDP-8/S a one bit processor because it implements arithmetic serially?