20 Feb
2015
20 Feb
'15
5:42 p.m.
On 2015-02-21 02:26, Chuck Guzis wrote:
On 02/20/2015 04:44 PM, ben wrote:
Misunderstanding 1: a char do not need to be 8 bits.
Also, an int is defined to be whatever size makes most sense on a
machine. It can be any number of bits. The only thing guaranteed is that
an int is between a short and a long in size. (They can all be equal.)
All that said, much C code make way more assumptions than the standard
allows. Plenty of sloppy programmers around.
And all that said, I do think the basic "unit" must be the same in all
places. So if you report sizeof as 9-bit chunks somewhere, it needs to
be 9-bit chunks everywhere else as well.
So you cannot have sizeof(int) == sizeof(char), unless they actually
contain the same number of bits. And since sizeof returns an integer,
you pretty much also needs to make one a multiple of the other as far as
number of bits goes.
Johnny
--
Johnny Billquist || "I'm on a bus
|| on a psychedelic trip
email: bqt at softjar.se || Reading murder books
pdp is alive! || tryin' to stay hip" - B. Idol
How do handle byte operations in C like *x++ on a
PDP 10?
I'm only passingly familiar with fORTRAN on the PDP-10, not C. But the
tapes that I've worked with packed 5-7 bit characters into a word with a
bit left over. In C, does an int have to be an exact number of chars long?
But, for that matter, how do you handle byte operations if they're not 6
bit/12 bit on a CDC 6600 in c? (60 bit words).