15 Mar
2001
15 Mar
'01
5:55 p.m.
It was thus said that the Great jpero(a)sympatico.ca once stated:
Odd, that actually sounds like the program is jumping through a NULL
long pointer. On the Intel x86 platform, the first interrupt vector is the
Divide by 0 trap, and on the 8086/8088/80186, the vector table resides in
the first 1K of memory, so an address of $0000:0000 (or $00000 depending
upon how you write it) so jumping to that address gives the indication of a
divide by zero exception.
-spc (Remembers way more than he wants to 8-)
DOS being unprotected could crash, usually after
the application
wiped it from memory like CP/M! Any unprotected OS would be
vunerable to being smashed by a runaway app.
Correct. Even I can lock up that Eazy PC with one of own DOS command
found in that dos directory, remember those / by 0 error in 40
columns due to quirky V40 cpu in that thing.