31 Dec
2005
31 Dec
'05
6:07 p.m.
Charles declared on Saturday 31 December 2005 20:32:
When I examine memory at 173000 it's all 1's
(177777) but I can
deposit and read data correctly into locations there. Shouldn't
the bootstrap program be copying its code there?
No. Because of 16-bit addressing vs 18-bit addressing, what the ODT
shows at 173000 is really "memory"/IO address 773000.
Again, if the
HALT line is being set for some reason, then the copy operation
can't take place... is that where I should be looking or am I
following a false trail?
There's no copy, reading from address 173000 gets translated by the MMU
to 773000 automagically.
Pat
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