What is the distance from the center of the spindle to
the "directory
track" (giving myself LOTS of wiggle room) on an 8" disk? Surely radius
is more inportant than diameter :-)
IIRC, most 8" drives were 48tpi, and had 77 cylinders. What I don't know
is the radius of the outside cylinder (which would be track 0 on side 0
IIRC). It's got to be A little under 4", of course. I don;t have a spare
8" disk to rip apart and measure the diameter of the magnetic disk
itself, nor do I know how far in track 0 is fro mthe edge of the disk.
Once we know that, obvious places pf the directory are on track 0, track
1 (allowing track 0 to be used for a bootstrap) and track 38 (in the
middle). Which would be 0, 1/48" and 38/48" in from the position of track 0.
[Yes I did once -- but only once -- make the mistake of forgetting to
divide the change in diameter by 2 when turning a metal part. In other
words I thought 'Oh, I need to take 50 thou off the diameter' and then
moved my cutting too in my 50 thou (in several passes of course) on the
lathe. Result : the part was undersized, I'd reduced the radius by 50
thou, and thus the diameter by 100 thou.
I am otld some Americal lathes have the cross-slide calibrated so that
the cutting tool moves half the distance it claims, the side is
calibrated for the change in diameter. British lathes do what they say,
the slide is calibrated for the actual distance the tool moves. Which is
actually more convenient, particualrly if you also do milling or drilling
in the the lathe.]
-tony