24 Sep
2015
24 Sep
'15
8:11 a.m.
On 9/24/2015 2:04 AM, ben wrote:
On 9/23/2015 11:22 PM, Eric Smith wrote:
0-99 can hold a trimmed character set and 10 digits per int.
5 chars per word sounds right on decimal machine.
Logic operations would be on the digit rather the binary
level.
On a 1410 (or 1401) 0-63 can hold the entire character set using
char/int conversion instead of storing chars as their native bits, and
then we have 5 digits per int as the native integer size (size of an
address).
0-127 would be required to hold a character with a work mark bit, which
I think one would probably want to make available at a character level,
but try and avoid having them set inside of ints.
Also, on a 1410 or a 1401 with the right optional features, bitwise
operations (bitwise &^|) could still be carried out on a binary level
without undue difficulty.
As you say, logic operations (&&, ||) would presumably use int 0 and 1 -
but could still be carried out on a binary level.
This may not be standard C but I has the early
PDP 11 C feel if they I developed UNIX on decimal machine.
Ben.
Precisely.
JRJ