On Mar 28, 2018, at 2:32 PM, Fred Cisin via cctalk
<cctalk at classiccmp.org> wrote:
> How many drives would you need, to be able to
set up a RAID, or hot swappable RAUD (Redundant Array of Unreliable Drives), that could
give decent reliability with such drives?
> How many to be able to not have data loss if a second one dies before the first
casualty is replaced?
> How many to be able to avoid data loss if a third one dies before the first two are
replaced?
On Wed, 28 Mar 2018, Paul Koning wrote:
...
The basic assumption is that failures are
"fail stop", i.e., a drive refuses to deliver data. (In particular, it
doesn't lie -- deliver wrong data. You can build systems that deal with lying drives
but RAID is not such a system.) The failure may be the whole drive ("it's a
door-stop") or individual blocks (hard read errors).
So, in addition to the "RAID" configuration, you would also need additional
redundancy to compare multiple reads for error detection.
At the simplest level, if the reads don't match, then there is an error.
If a retry produces different dataa, then that drive has an error.
If two drives agree against a third, then there is a high probability that the variant
drive is in error.
If you don't trust drives to deliver correct data often enough, you need your own
error detection. Comparing redundant copies is possible. More efficient is various EDC
or ECC codes. Some file systems used hashes like SHA-1 to detect data corruption with
extremely high probability.
...
So one way to look at it: given the MTBF,
calculate the probability of two drives failing within N hours (where N is the time
required to replace the failed drive and then rebuild the data onto the new drive). But
that is not the whole story.
'course not. Besides MTBF for calculating the probability of a second drive failing
within N hours, must also consider other factors, such as external influences causing more
than one drive to go, and the essentially non-linear aspect of a failure rate curve.
Yes, RAID has an underlying assumption that drive failures are independent random events.
If that isn't valid then you have a big problem. This occasionally happens; there
have been drive enclosures with inadequate mechanical design, resulting in excessive
vibration which caused rapid and correlated drive failure. The answer to that is
"test it properly and don't ship stuff like that".
The other part
of the story is that drives have a non-zero probability of a hard read error. So during
rebuild, you may encounter a sector on one of the remaining drives that can't be read.
If so, that sector is lost.
If we consider that to be a "drive failure", then we are back to designing
around multiple failures.
Correct, and that is why RAID-6 is prevalent now that drives are large enough that there
is a nontrivial error of getting a sector read error if you read the whole drive (as
RAID-1 rebuild does) and especially if you read multiple whole drives (as in RAID-5).
The probability of hard read error varies with
drive technology. And of course, the larger the drive, the greater the probability (all
else being equal) of having SOME sector be unreadable. For drives small enough to have
PATA interfaces, the probability of hard read error is probably low enough that you can
*usually* read the whole drive without error. That translates to: RAID-1 and RAID-5 are
generally adequate for PATA disks.
"generally".
The original thought behind this silly suggestion was whether it would be possible to
make use of MANY very unreliable drives.
Definitely. You'd have to analyze the model just as I described. If things are bad
enough, you may find that RAID-6 is inadequate and you instead need a N-fault redundant
code with N>2. Such things are mathematically straightforward but compute intensive.
I've seen this done in the "Self-star" distributed storage research system
at Carnegie-Mellon about a decade ago. Partly the reason was to deal with cheap
unreliable devices, and partly was as an intellectual exercise "because we
can".
paul