5 Feb
2002
5 Feb
'02
6:08 p.m.
On Wed, 6 Feb 2002, Cini, Richard wrote:
In the body of the routine, the variable can be set
to three values
using #defines from the header. For some reason, the variable is not being
set to the #define value. As you trace execution, the variable to be
returned by the routine remains 0xcccccccc after assignment:
nSioStatus = SIO_WDB ; //#defines to 0x80
So you're saying if you added a printf("%x", nSioStatus) right here (after
the assignment) you'd see 0xcccccccc?
So, I initialized the variable to 0 and for good
measure, returned
the int as:
return (nSioStatus & 0xff) ;
In one of the top calling routines, it gets truncated to a BYTE-size
(so to speak) anyway.
Maybe because you are returning effectively a byte? Try type-casting the
returned value:
return ((int)(nSioStatus & 0xff));
I don't know if that actually addresses your main problem directly.
I also like Bryan's suggestion to check for out-of-bounds writes on a
malloc'd memory buffer. That sort of thing causes really weird shit to
happen.
Sellam Ismail Vintage Computer Festival
------------------------------------------------------------------------------
International Man of Intrigue and Danger http://www.vintage.org
* Old computing resources for business and academia at www.VintageTech.com *