9 Jun
2004
9 Jun
'04
7:59 a.m.
Rumor has it that Doc Shipley may have mentioned these words:
Steve Thatcher wrote:
Yes. ;-)
-=-=-=-=-=-=-=-
They're 256K*bit* chips, so it takes 8 (or 9 if you use parity) chips to
make 256K*byte*s of storage. So, just saying "256K" isn't quite enough
information to enumerate exactly what's meant...
hmmm, I thought there were four rows of 18 chips.
That sounds like 8
banks of 256K which seems
like 2meg to me... unless I got something wrong
No, I guess I got it wrong. I thought you meant 256K per chip, or 4MB
per bank (16 * 256K plus 2 * 256K for parity).
So are these 256K per bank, or 256K per chip? IOW, if they turn out to be compatible and I install
16 of them on the
Amiga A2091, will that be a 2MB or 0.25MB upgrade?
Neither -- 16 would give you a 0.5MegaByte upgrade. 8 would give you 0.25MB.[1]
Heh. I'd rather stick my face in the mud....
[family joke]
My brain's *way* too frelled up right now to get into that...
Vioxx & Beer -- *bad* combination. My Doc (not you, Doc ;-) says I gotta
keep taking the Vioxx, so no beer. :-((~~
HTH,
Roger "Merch" Merchberger
[1] I figured I shouldn't mention until later that the upgrade you mention
would give you 256K*words* of memory, as the Amiga's a 16-bit machine... 4
bits = nybble, 8 bits = byte, CPU data width = word. (The last part is a
bit simplistic, but...)
--
Roger "Merch" Merchberger | "Profile, don't speculate."
sysadmin, Iceberg Computers | Daniel J. Bernstein
zmerch(a)30below.com |