12 May
2006
12 May
'06
2:24 p.m.
On Fri, 12 May 2006, Roger Merchberger wrote:
Rumor has it that Brian L. Stuart may have mentioned
these words:
I was thinking of that (and was also suggested by a cow-orker) but I was
unsure about how to handle the function of variable resistance WRT heat
dissipation; and also, if a bulb fails, it fails open-circuit which means
there's no more voltage regulation. I suppose with enough bulbs, one could
build enough redundancy into the system...
I may hit an auto-parts store tomorrow anyway and see what I can scare up;
but having ready access to several CPUs (2 each 80486SX's & a P75 Overdrive
on a quick search) I figured that a 5V CPU would be a good way to dissipate
power from a 5V source, and the 486 would prolly have the highest current
draw of any easily available 5V processor.
But again, I could very well be wrong...
No, I'm *not* using any of my 6809s!!! ;-)
Thanks!
Roger "Merch" Merchberger
--
Roger "Merch" Merchberger | "Bugs of a feather flock together."
sysadmin, Iceberg Computers | Russell Nelson
zmerch at 30below.com |
A bare 486 will probably not draw enough power, especially if it not on a
working motherboard (its 1u CMOS so mainly draws dynamic power - no clock - no
power)
Peter Wallace
From:
Roger Merchberger <zmerch-cctalk at 30below.com>
The problem is I need to use a PC power supply (AT-class with it's own
power switch) as a 12V power source, and the only one I have access to
needs a minimum load of 3Amp on the +5Volt line.
How about a light bulb?