11 Feb
2004
11 Feb
'04
7:43 a.m.
Witchy wrote:
No, because just like Linux, idle processes will be swapped out to leave
memory available for immediate demands, primarily buffers. Task
manager doesn't reflect what portion of memory is used for what purposes
very accurately. IIRC, there's a tool out on <
http://www.sysinternals.com > that gives a more detailed view of what is
allocated where.
--jc
-----Original
Message-----
From: cctalk-bounces(a)classiccmp.org
[mailto:cctalk-bounces@classiccmp.org] On Behalf Of J.C. Wren
Sent: 11 February 2004 05:23
To: General(a)jupiter.easily.co.uk;
Discussion@jupiter.easily.co.uk:On-Topic and Off-Topic Posts
Subject: Re: Yay - new DEC arrival (not *strictly* on topic.
Or is it?)
I think your understanding of operating systems and PC
architecture is flawed. It sounds like typical knee-jerk MS bashing.
Not really, I'm running Win2K Pro here on a 'standard' system with half a
gig of RAM which requires me to have a gig's worth of pagefile. Why? Surely
half a gig is enough memory to have all my running processes in memory at
the same time, even if they're inactive? According to the task manager I've
got 210mb 'free', so everything that's running now should stay running and
not get swapped out, but it does.
Cheers
--
Adrian/Witchy
Owner & Webmaster, Binary Dinosaurs
www.binarydinosaurs.co.uk - possibly the UK's biggest online computer museum
www.snakebiteandblack.co.uk - ex-monthly gothic shenanigans :o(