Richard wrote:
Speaking of wiring up test load resistors for a PSU,
just exactly how
do you go about deciding what resistance and what power rating to use
for a test load?
For a basic test, where we just want to verify that the PSU works
properly near its maximum rated load:
rated voltage = E
rated current = I
resistor value = R = E/I
resistor wattage = P = E*I = E^2/R
For instance, for a 5.2V 35A power supply, R = 5.2/35 = 0.149 ohms. We
aren't going to find an actual 0.149 ohm resistor, but rounding up a bit
we can find 0.15 ohm. With that, I = E/R = 5.2/0.15 = 34.67A, near the
maximum rated current, and P = (5.2^2)/0.15 = 180.27W.
Note that we have to bolt that resistor to a good heatsink, and provide
force air cooling, to prevent it from burning up. A 0.15 ohm 200W
resistor is roughly 2" diameter by 3" long, which is not much volume (or
surface area) for 181W of heat.
We can buy a chassis-mount 0.15 ohm 200W resistor from Mouser
Electronics, but it costs $46, and that resistor probably won't be of
much use to us for anything other than testing that particular power
supply. We might be better off buying more resistors of a more common
value and paralleling them, or buying a variable resistor.
With variable resistors (rheostats) we have to be careful, because the
power dissipation rating is at the maximum resistance, and for lower
resistance we have to linearly derate the power. For instance, we could
try using a 225W 1 ohm variable resistor, but when we set the tap at
0.15 ohms, we now have to derate the power to only 33.75W. That won't
meet our requirements.
Suppose instead we parallel 33 5 ohm resistors. That gives us an
overall resistance of 0.152 ohms, and power dissipation of 5.2W each.
We can use resistors that cost us $0.93 each. In total, that is
$30.69. We haven't saved much money over the single resistor, and now
we have to expend more effort in wiring the resistors up to form the
load, but it's far more likely that we'll be able to reuse those
resistors for a different power supply load in the future.
To do "serious" power supply testing, we would need to measure line
regulation and load regulation. For load regulation measurement, we can
put a solid-state relay in series with some of our parallel resistors,
so that we can near instantaneously change the load current (load step),
and watch the supply voltage change on an oscilliscope.
Lyle Bickley and I built the test loads for the DEC 728 power supplies
of the PDP-1. We did not test line regulation and load regulation for
step response; we just tested the power supply under four different load
conditions, and measured the DC voltage, RMS ripple, and peak-to-peak
ripple of each output under each of the four load conditions, with a
variac on the input at 105V, 115V, and 125V. Testing the 728 is
complicated by the fact that it is a dual output supply, providing +10V
and -15V. There is a maximum current rating for each output, but there
is also a maximum overall power, such that one cannot draw the maximum
current from both outputs simultaneous. We built the load box with a
rotary switch to select load combinations of:
+10V at 0.2A, -15V at 0A
+10V at 7.5A, -15V at 0A
+10V at 0.2A, -15V at 8.5A
+10V at 2.0A, -15V at 7.0A
Eric