6 Dec
2002
6 Dec
'02
4:20 p.m.
There are low-dropout regulators that can do this, but
they are more expensive.
Another thing I've done in thes3
--- Ethan Dicks <erd_6502(a)yahoo.com> wrote:
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[ACE PSU]
...a 7805 1A linear regulator which needs around
8V to 15V to run properly.
So I was thinking about this recently... I have this
6V battery
pack that is intended to clamp to the back of a ZIP
drive, allowing
it to be used away from power, say with a laptop.
I've wanted
to use it for a portable source of juice for hobby
projects (it
has, among other features, a built-in 110V mains
plug and recharger,
making it handy to recharge), but I haven't expected
to be able to
feed a 7805 at +6VDC and get +5VDC out the other
side reliably.
How can I take +6VDC of battery power and get +5VDC
regulated power
from it? If it matters, the currents involved will
be under 1000mA,
but probably over 200mA.
-ethan
P.S. - I don't mind the concept of a DC-DC
converter, but I'm not
skilled enough to design one, just skilled enough to
build it.
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