other
parameters). You won't see the normal 2-diode behaviour with
those.
Why not? Except for higher forward drop on the B-E pins (because it's
actually two B-E junctions in series), I don't see any reason you
wouldn't see basically two-diode behaviour from a Darlington pair.
OK, you do see the expected 2-diode behaviour (apart from the
double-sized b-e voltage drop) if the thing is working correctly. Problem
is that it can still show that behaviour if it's failed. Suppose the b-c
junction of the second transistor is open. C-E wil lbe open both ways
round, B-C will be open oen way and one diode drop (that of the B-C
juntion of the first transistor) the otehr, B-E will be open oen way and
2 drops the other way. But that is not going to be a useful power device...
> 1st - b-e 1.95V e-b 0.82V b-c OC c-b 0.66V
c-e 0.58V e-c OC
> 2nd - b-e 1.91V e-b 0.83V b-c OC c-b 0.68V c-e 0.58V e-c OC
> 3rd - b-e 1.90V e-b 0.81V b-c OC c-b 0.67V c-e 0.59V e-c OC
> 4th - b-e 1.75V e-b 0.75V b-c OC c-b 0.56V c-e 0.58V e-c OC
This is..strange. Combined with the above, I'm led to suspect that
what you people are calling a Darlington pair is not what I thought it
was. I thought a Darlington pair was two bipolar transistors of the
same kind (both NPN or both PNP) in a single package, connected
internally like so:
---------------
| |
| -----+---|----c
| | | |
| --- | |
| | c| | |
b----|--|b | | |
| | e| | |
| --- --- |
| | | c| |
| --|b | |
| | e| |
| --- |
| | |
| ---|----e
| |
---------------
Basically, that's what is is. Sometimes there's a resistor between the
b-e of the second transistor inside the package. And sometimes (as here)
there'sn inernal diode between C-E which is reverse-biased in normal use.
-tony