16 May
2005
16 May
'05
3:04 p.m.
On Mon, 2005-05-16 at 14:33 -0700, John Hogerhuis wrote:
On 5/16/05, Dave Dunfield <dave04a at
dunfield.com> wrote:
... the wrong answer being to dump out each array element followed by a
comma, then output ^H as the final step in the function ;-)
Real Programmers would presumably use putc exclusively in favour of the
more computationally expensive printf...
cheers
J.
Given that the original example assumes n > 0
(the test is skipped on
first entry to the loop), you can accomplish this function with neither
an extra conditional, superfluous assignment, extra variables or use
of 'goto'
void print_arg(int *aryp, unsigned n)
{
int i;
for(i=0; ;) {
printf("%u", aryp[i]);
if(++i >= n)
break;
fputs(", ", stdout); }
putc('\n', stdout);
}
Now that's a right answer.