kVA is simply kilovolts times amps. It is roughly a synonym for kW, except that it
probably ignores the phase angle. So for resistive loads, kVA == kW but for inductive or
capacitive loads, kVA would be larger.
1 hp == 746 W. But when people talk about phase converter hp limits, they are looking not
just at the steady state load but also at the startup peak current, which is a fairly
substantial multiple of the steady state load.
For your application, you probably have some motor loads and possibly some others (power
supplies). If they are mostly motor loads, use the steady state kVA spec and convert that
back to hp by dividing by 0.746. Alternatively, if the converter has a rated steady state
load, match that against the steady state power spec for the machine. The peak current
handling of the converter will take care of either motor startup peaks, or power supply
inrush current.
paul
On May 4, 2017, at 10:36 AM, Guy Sotomayor Jr via
cctalk <cctalk at classiccmp.org> wrote:
Does anyone know how to convert KVa to 208v 3-phase currents and/or HP? IBM?s docs all
specify power in KVa and most of the 3 phase converters (other than what Bob posted) seem
to specify HP. If I?m going to spend serious coin on a phase converter (I think I found
it online for ~$3k?ouch!), I want to make sure it?s sized properly.
Thanks.
TTFN - Guy