[cctalk] Re: Use (abuse?) of a 7924 in a +24 PS...

Hi Tony, Thanks for the reply. This is what it looks like to me (I hope this comes out): AC--- + ---------------------------------------------------FD400 +24 | | | | ---------------- |+ left| |right | BR2 C4 2200uf 50V 7924 | |- |center | | | | | B | AC--- - ----------------------E 2n6045 C--------------FD400 common 2n6045 E/B/C are according to the silkscreen. The actual physical pins are: B-left, C-center, E-right. Left, right, center designations are with the tab up for both devices. As far as I can tell, there are no other components (capacitors, resistors, diodes) involved in the circuit. I'm measuring a smooth +41 volts at the FD400 connector with some 24volt automotive bulbs as load. In case the above is illegible, Circuit is: AC to bridge rectifier. BR+ goes straight to FD400 +24. BR- goes to 2n6045 right pin. BR +/- connected with a 2200uf 50V electrolytic cap. 7924 left pin goes to BR+. 7924 center pin goes to 2n6045 left pin. 7924 right pin goes to FD400 common. 2n6045 center pin goes to FD400 common. Maybe I'm not loading it enough? I'm very hesitant to reattach the FD400 until I understand this. By the way, plus and minus five volts are fine. Bill -- This email has been checked for viruses by Avast antivirus software. www.avast.com