Yes, that is certainly the problem. Presumably more current is flowing
through the current sense resistor than should be.
Do you mean when the power supply is connected to the mains here?
If we are still talking about the test case when you are applying an external
supply to Vstart only, there should be almost zero current flowing through
the 51 Ohm current sense resistor because the chopper is not operating
because it has no HV supply.
We can calculate the current flowing through the current sense resistor
using Ohm's law given it's resistance and the voltage across it so we
don't need to presume.
I thought that perhaps
the higher positive voltage might be enough to switch on the rectifier diode
while the lower positive voltage on the good PSU won't,
My feeling is that (in the test case with external Vstart only) the -12V
rectifier diode is being caused to conduct by the forward bias voltage applied
to it from Vstart/V2 (should that be Vz I wonder?) via the 16k9 resistor, the
75k resistor and the wound components. The current available to flow through
the diode is limited to some microamps by the 75k resistor. As Brent said,
this is very low on the diode's characteristic curve and there are likely to
be variations between the voltages dropped across different diodes.
If diode was not present in the circuit, approx 4V (which IIRC you measured
at E1b non-inverting input) should appear across the points where the diode
would have been. It is more the characteristic of the diode which is
determining how much voltage is appearing across itself than anything else.
The other components involved have little say about what voltage appears
across the diode. They just allow a small current to flow through the diode
to forward bias it and the diode gets to decide how much voltage then appears
across itself, depending on the magnitude of the current flowing through it
when forward biased and it's characteristic curve.
but it seems to
switch on in both cases because I measured a voltage across the current
sense resistor in both cases. I measured 0.08V on the bad PSU and 0.01 on
the good PSU. So this would explain why an over current is being detected.
0.08V across a 51 Ohm resistor suggests that approx 1.6mA is flowing through
it from Ohm's law. 0.01V across the same resistor suggests that approx 200 uA
flowing through it. I assume this is with the power supply connected to the
mains, not using the external supply to energise Vstart only as I can't see
where 1.6mA would come from in the latter case.
1.6mA being drawn from the -12V supply is not suggestive of an overload
unless it's capacity is very limited indeed. Perhaps this is the normal
expected loading? 200uA seems very low indeed but perhaps this is to be
expected? If the -12V line is not being produced, the load cannot draw
any current from it. I don't think that either of these conditions should
trigger an overload response from the PSU.
(Are the 0.08V and and 0.01V voltages appearing in the same direction or
is one of them positive and the other one negative?)
(Does the resistor measure approximately 50 Ohms in both cases with the
power switched off)?
What I don't now get is why the -12V output is higher on the bad PSU because
if there is something shorted or a capacitor with high current leakage on
the -12V output, that would surely result in a lower voltage on the -12V
output, not a higher one?
Sorry, this is not very clear to me and I already get confused enough when
dealing with negative supply rails. The -12V output being higher could
refer to it's voltage being more positive with respect to 0V or it's voltage
being more negative with respect to 0V. In any case, I'm not sure I recall
what the voltages measured on the -12V lines of the working and non-working
power supplies were with them connected to the mains. I think I recall they
were +0.6V and +0.4V respectively when power was applied to Vstart only.
I think it is likely that most of what we are seeing here is to be expected
and is explainable either by the test conditions created by applying power
to Vstart only or by conditions created by the presence of the fault and
not necessarily because we are close to the location of the fault.
I think the next step might be to check what is happening with the
comparators. Are their positive power supply pins connected to Vstart or
V2 (Vz?) or somewhere else? Are their negative supply pins connected to 0V
or maybe to the -12V line or maybe somewhere else? Are they getting suitable
volages on both supply pins that will enable them to operate under startup
conditions? If either the positive or negative supply to one or more of
them is missing or wildly incorrect at startup, they cannot be expected to
do their jobs properly.
It might be worth doing some more testing without a mains supply connected
but with an external supply for Vstart and also an external negative supply
going to the -12V line via a 2k7 resistor to mimic both the positive and
negative startup supplies on sheet 1. Comparing (no pun intended) what
appears on the positive and negative power supply pins of the comparators
between the working and non-working power supplies under these conditions
might reveal something.
If the two behave similarly, it may be time to focus on whether the
comparators in the faulty PSU are behaving correctly. However, I would
be wary of attempting to make tests around any of the comparators with
the mains supply connected to the PSU in case of inadvertently disabling
a protection circuit which could be detecting and protecting against a
real overload. This would probably lead to something going bang :-(
I hadn't noticed the connection to -12V on the non-inverting input of E1b.
However, I don't think this can account for the 0.6V because in both
the working and non-working PSUs the non-inverting input to E1b is 4V.
See further down.
However,
when I was checking this, I noticed that I must have made a mistake,
because the -12V output actually measures +0.4V on the working PSU
(not zero as I first thought), but the non-working PSU measures +0.6V.
Also, I noticed that the -12V output on the working PSU rises more
slowly to +0.4V than on the non-working PSU where it rises more quickly
to +0.6V.
I still don't understand where this +ve voltage on the -12V output can
come from though? Whether on the working PSU or the non-working PSU.
The 4V at the non-inverting input of E1b is linked to the -12V line via the 75k
resistor and from there via a smoothing choke and the chopper transformer
secondary to the -12V line rectifier diode connected to pin 6 and on to
ground via the parallel diode/resistor combination. This should result in
a current of about 45 microamps flowing to ground through those components
mentioned.
This in turn should cause the rectifier to be forward biased and drop
approximately 0.6V across it which is characteristic of silicon diodes.
Does that make sense?
It took me a while to understand this, but yes I get that now.
To expand a little further, I got the 45uA by applying Ohm's law to the 75k
resistor with 3.4V across it. All the other resistances in series would be
negligable compared to 75k.
(It's rather confusing in that the -12V line rectifier is on the ground side of the
chopper transformer secondary instead of on the supply side where it would
more usually be encountered. It's electrically all the same wherever it
is put as the components involved are in series anyway.)
It ought to be possible to measure the same 0.6V across the diode to confirm
this
is where it is being dropped (and to measure the remaining 3.4V of the
4V at E1b across the 75k resistor). As to why it is only 0.4V on the working
power supply, I haven't thought that far ahead yet :-)
On the bad PSU I measure a 0.48V drop across the rectifier diode (the one
directly connected to the transformer, not the one in parallel with the
current sense resistor), on the good PSU I measure a 0.4V drop.
This seems reasonable given what Brent was saying about variation in
diode characteristics when the current through them is very low.
Regards,
Peter Coghlan.
I think the +0.6V on the -12V line is explainable
and to be expected under the
test conditions described. It looks like there could be something wrong in the
control circuitry which is preventing the power supply from starting up.
This might also account for the difference between the 0.4V and 0.6V.
Brent's suggestions for checking the condition around the comparators and
how they are supplied with power are good ones. I haven't made any
further
suggestions because I don't have any right now :-)
I had forgotten about Brent's suggestion. Still need to check this.
Regards,
Peter Coghlan.